with following function prototype and structure of linked list, how do i write function to return an address/? I think what I got is wrong. please help
prototype:
struct node *search(struct node *start,int n);
structure:
struct node { int value; struct node * next;};
Code:struct node *search(struct node *start,int n) { if ( n = node->value) return node; else return (\0); }
Nope, that's correct. If you want to return a pointer to a structure, you just do:
return node;
Quzah.
Hope is the first step on the road to disappointment.
i should be explicit in what the function needs to do:
- if value n is found in some node, return address of this node
- if value n is not found, return null pointer
so is what i have okay??
Right. That's what you want. That's what you've got.
That's exactly what you have. You're doing it right.Code:Node *myFunc( Node* searchHere, int findThis ) { Node *n; for( n = searchHere; n; n = n->next ) if( n->value == findThis ) return n; return NULL; }
Quzah.
Hope is the first step on the road to disappointment.
