function shift

This is a discussion on function shift within the C Programming forums, part of the General Programming Boards category; Hi, Trying to make the letters ABCDE shift by one by calling in five times i.e. BCDEA, CDEAB, DEABC, EABCD, ...

  1. #1
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    Unhappy function shift

    Hi,

    Trying to make the letters ABCDE shift by one by calling in five times i.e. BCDEA, CDEAB, DEABC, EABCD, and ABCDE.

    Here's what I got and I know it's probably easy and I'm hosed up, but I'm an extreme noob at programming.

    Thanks in advance.

    Code:
    #include <stdio.h>
    
    int main(void)
    
    char  c1 = 'A', c2 = 'B', c3 = 'C', c4 = 'D', c5 = 'E';
    char *p1 = &c1, *p2 = &c2, *p3 = &c3, *p4 = &c4, *p5 = &c5;
    
    void shift(char *p1, char *p2, char *p3, char *p4, char *p5)
    {
    	shift(&c1, &c2, &c3, &c4, &c5);
    	return 0;
    }

  2. #2
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    The tutorials section is the one that you should be heading to right now. Your code is so messed up, that i think you should start right from a hello world program. Also, you dont specify what you want to do with the shifted letters. Your aren't shifting them in an array, so i really dont understand what you intend to do.
    Code:
    >+++++++++[<++++++++>-]<.>+++++++[<++++>-]<+.+++++++..+++.[-]>++++++++[<++++>-] <.>+++++++++++[<++++++++>-]<-.--------.+++.------.--------.[-]>++++++++[<++++>- ]<+.[-]++++++++++.

  3. #3
    Registered User ssharish2005's Avatar
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    Cambridge, UK
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    mattflick this is not complete proper programe. you got many error in it. pointing out the error,
    you havn't got the completed main fucntion.
    you cant assign a value for an pointer
    you cant use shift as an fucntion identifier as it is a inbuilt function identifier

    and the proper code for you problem

    Code:
    #include<stdio.h>
    
    void shiftchar(char *p1, char *p2, char *p3, char *p4, char *p5)
    {
        char temp;
        
        temp=*p1;
        *p1=*p2;
        *p2=*p3;
        *p3=*p4;
        *p4=*p5;
        *p5=temp;
    }
    
    int main()
    {
        char  c1 = 'A', c2 = 'B', c3 = 'C', c4 = 'D', c5 = 'E';
        int i;
        
        for(i=0;i<5;i++)
        {
            shiftchar(&c1,&c2,&c3,&c4,&c5);
            printf("%c %c %c %c %c\n",c1,c2,c3,c4,c5);
        }
        
        getchar();
    }
    /*my output
    B C D E A
    C D E A B
    D E A B C
    E A B C D
    A B C D E
    */
    and the better way of doing this using by string of char(strings)

    -ssharish2005
    Last edited by ssharish2005; 09-29-2005 at 03:12 AM.

  4. #4
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    Thanks so much for your help. I'm learning I just need more experience looking all the different types code for all there different applications. Thanks again for the help.

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