Thread: Help, weird problem setting variable

  1. #1
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    Help, weird problem setting variable

    Im stumped...
    Here is a small snippet of code:

    Code:
     
      float W = 640;         //(float)SCREEN_WIDTH;
      float BIG_H = 480;     // (float)SCREEN_HEIGHT;
      printf("BIG_H %d %f\n", BIG_H, BIG_H);
    
      BIG_H = 480.0;
    
      printf("BIG_H %d %f\n", BIG_H, BIG_H);
    The screen output is
    BIG_H 0 0.00000

    Any ideas why?
    Last edited by sloppy_coder; 09-25-2005 at 02:14 PM.

  2. #2
    and the hat of int overfl Salem's Avatar
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    Well there's nothing like living up to a nickname...

    Obviously, the "<< !! Posting Code? Read this First !! >>" slipped your attention.

    Oh, and to answer your question, the reason is your printf conversion characters are wrong.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

  3. #3
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    Wow you're touchy. fixed.

    btw.
    a couple of lines down i have more 'sloppy' code.
    Code:
     printf ("W = %f , H = %f , W/H = %f\n", W, BIG_H, screen_ratio);
    same conversion character %f.. and the output is:
    W = 640.0000 , H = 480.00000 , W/H = 1.333333

    Why does %f work in this case?

  4. #4
    and the hat of int overfl Salem's Avatar
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    Perhaps reading the manual page for printf() would help.
    Basically, you've got to get the conversions consistent with the parameters or it just doesn't work.
    If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
    If at first you don't succeed, try writing your phone number on the exam paper.

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