Thread: hi..stuck in sorting

  1. #1
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    hi..stuck in sorting

    hi..i try to implement the bubble sorting where it read from file..i mean line by line then break into token..it can break into token but it can't sort the words..
    Eg. input
    Code:
    "this is a string"
    output from the program.
    Code:
    "this
    is 
    a 
    string"

    output that i want..
    Code:
    "a 
    is 
    string 
    this"
    it seems like it din't pass any value into the bubbleSort..my bubble sort function can work with character by character but i jus want it works by words by words..can give some tips where i did wrong in my program??..thanks..

    here is the program:
    Code:
    /* header file */
    #include <stdio.h>
    #include <stdlib.h>
    typedef char* Item;
    Code:
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    #include "b.h"
    #define M 50
    
    
    int main()
    {
        FILE *infile, *outfile;
        char line[1000], words[1000];
        char *token;
        char temp[1000];
        char *filename = "test.txt";
        char *delimeter = " ";
        
        if((infile = fopen(filename, "r")) == NULL)
        {
           printf("Error");
        }
        
        if (fgets(line, sizeof(line), infile) != NULL)
        {
    
        printf("%s\n", strtok(line, " "));
    
       while ( (token=strtok(NULL, " ")) != NULL)
       {
        bubble(&token, M);
        printf("%s\n", token);
        
       }
        
    }
        return 0;
    }
    
    void bubble(Item a[], int N)
    {
         int pass, pos;
         Item temp;
         for (pass = 1; pass < N; pass ++)
         
             for (pass = N - 1; pos >= pass; pos --)
             {
                 if (a[pos] < a[pos-1])
                 {
                     *temp = *a[pos];
                     *a[pos] = *a[pos-1];
                     *a[pos-1] = *temp;
                 }
             }
    }
    Last edited by cBegginer; 09-19-2005 at 10:12 AM. Reason: enter wrong output

  2. #2
    Fear the Reaper...
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    Is it just me or your output from your program is the same as the output you want (at least in your post) ?
    Teacher: "You connect with Internet Explorer, but what is your browser? You know, Yahoo, Webcrawler...?" It's great to see the educational system moving in the right direction

  3. #3
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    hey man..sorry..i had type wrong the original output..n the code had been edited..sorry..

  4. #4
    Frequently Quite Prolix dwks's Avatar
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    Code:
    for (pass = 1; pass < N; pass ++)
         
             for (pass = N - 1; pos >= pass; pos --)
             {
    Maybe that should be pos?
    dwk

    Seek and ye shall find. quaere et invenies.

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  5. #5
    Frequently Quite Prolix dwks's Avatar
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    Code:
        Item temp;
                 if (a[pos] < a[pos-1])
                 {
                     *temp = *a[pos];
                     *a[pos] = *a[pos-1];
                     *a[pos-1] = *temp;
                 }
    Get rid of the asterisks. temp is not a pointer.
    dwk

    Seek and ye shall find. quaere et invenies.

    "Simplicity does not precede complexity, but follows it." -- Alan Perlis
    "Testing can only prove the presence of bugs, not their absence." -- Edsger Dijkstra
    "The only real mistake is the one from which we learn nothing." -- John Powell


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  6. #6
    Information Crocodile
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    Your passing the string one by one.

    Code:
       while ( (token=strtok(NULL, " ")) != NULL)
       {
        bubble(&token, M);
        printf("%s\n", token);
        
       }
    The first loop will pass the word "this" and sort its character. The printf will print "ihts" which is the sorted "this" string. and itll do that with the other tokenized words.

    My suggestion is use a 2d array to pass the all strings. and use strcmp to compare strings.

    Code:
             for (pass = N - 1; pos >= pass; pos --)
             {
                 if (a[pos] < a[pos-1]) // replace this with strcmp
                 {
                     *temp = *a[pos];
                     *a[pos] = *a[pos-1];
                     *a[pos-1] = *temp;
                 }
             }

  7. #7
    Frequently Quite Prolix dwks's Avatar
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    You didn't notice . . .
    Code:
    for (pass = N - 1; pos >= pass; pos --)
    etc.

    A 2D aray is a good idea.
    dwk

    Seek and ye shall find. quaere et invenies.

    "Simplicity does not precede complexity, but follows it." -- Alan Perlis
    "Testing can only prove the presence of bugs, not their absence." -- Edsger Dijkstra
    "The only real mistake is the one from which we learn nothing." -- John Powell


    Other boards: DaniWeb, TPS
    Unofficial Wiki FAQ: cpwiki.sf.net

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  8. #8
    Registered User cbastard's Avatar
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    Code:
    char *token;
    bubble(&token, M);
    typedef char* Item;
    void bubble(Item a[], int N)
    Array of pointers is not pointer to a pointer.although it is logically correct in C.but it is confusing so better go for array

  9. #9
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    thanks

    hey..guys thanks for helping me out..

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