Print enum value

I'm trying to figure out how to print an enum variable name verses the enum value. currently my code looks something like this. It prints the numeral 0-2 verses the enum that corresponds with the value.

Code:

case win:
			++*win_cnt_ptr;
			//printf("%27sYou win.\n", "");
			printf("%s%d%s%d%s\n", "You chose ", player_choice, 
			" and I chose ", machine_choice, " You win.\n");
			break;

When this prints, the following text is printed:

You chose 2 and I choose 1 You win.

create an array of strings that contain the names you want, then use player_choice and machine_choice as the index into the string array.

Code:

char* names[] = {"One","Two","Three", ...}


printf("you chose %s\n", names[player_choice]);

http://cboard.cprogramming.com/showthread.php?p=186539

Code:

typedef enum
{  one,
   two,
   three
} myenum;


int main()
{
	char test[3][6]={"one","two", "three"};
	myenum value=two;
	char tmp[6]={0x0};
	
	strcpy(tmp,test[(int)value]);
	printf("%s\n", tmp);
	return 0;
}

Code:

#include <stdio.h>
#define X(x) #x

int main(void){
  int i = 9432;
  printf("%s = %d",X(i),i);
  return 0;  
}

(I don't think I read the question properly...)

I had this fixed by doing the following:

Code:

case win:
			++*win_cnt_ptr;
			//printf("%27sYou win.\n", ""); //old code
			printf("%s%s%s%s%s\n", "You chose ", names[player_choice], 
			" and I chose ", names[machine_choice], " You win.\n");
			break;

It was working sort of, except the logic wasnt quite right. Now when I went back to fix that, I seemed to have broken this. Ive been trying for the last two days to fix this and havent gotten anywhere. It will print the dec equiv but if I try to invoke printing the name, it crashes. When I take out the new code, the program still works.

Here is the response of the debugger if it helps.

Code:

>	Ch 7 Ex 5.exe!report(outcome result=win, int * win_cnt_ptr=0x0012fed4, int * lose_cnt_ptr=0x0012fec8, int * tie_cnt_ptr=0x0012febc)  Line 16 + 0x11	C

How is names declared? Are you trying to access beyond the end of the array?

Originally Posted by Ancient Dragon

create an array of strings that contain the names you want, then use player_choice and machine_choice as the index into the string array.

Code:

char* names[] = {"One","Two","Three", ...}


printf("you chose %s\n", names[player_choice]);

Don't forget an array index starts at zero. In this example, if the user enters the value 1, the program will print "you chose Two". So, make names:
char* names[] = {"Zero", "One","Two","Three", ...}

I'm going to post the whole section of code. The program itself spreads itself over 5 files. The logic I used was to return the players_choice and machine_choice to report.c. The problem seems to be that my print statements no longer print the enum value 0, 1, or 2. I get a number 8-10 digit integer number instead. Its like they are calling something else. Its quite frustrating.

Code:

#include "p_r_s.h"

void report(outcome result, int *win_cnt_ptr, 
			int *lose_cnt_ptr, int *tie_cnt_ptr, p_r_s player_choice, p_r_s machine_choice)
{

// New code added to address arrary to variable name conversion
char* names[] = {"paper","rock","scissors"};
// End new code	

	switch (result) {
		case win:
			++*win_cnt_ptr;
			//printf("%27sYou win.\n", "");
			printf("%s%d%s%d%s\n", "You chose ", player_choice, 
			" and I chose ", machine_choice, " You win.\n");
			break;
		case lose:
			++*lose_cnt_ptr;
			// New code
			//printf("%s%s%s%s%s\n", "You chose ", names[player_choice], 
			//" and I chose ", names[machine_choice], " You lose.\n");
			// End new code
			
			printf("%27sYou lose.\n", ""); // Old Code
			break;
		case tie:
			++*tie_cnt_ptr;
			
			// New Code
			//printf("%s%s%s%s%s\n", "You chose ", names[player_choice], 
			//" and I chose ", names[machine_choice], " A tie.\n");
			// End new code

			printf("%27sA tie.\n", ""); // Old code
			break;
		default:
			printf("PROGRAMMER ERROR:  Unexpected result!\n\n");
			exit(1);
	}
}

Try this:

Code:

#include <stdio.h>

typedef enum
{
  WIN,
  LOSE,
  TIE
} outcome;

typedef enum
{
  CHOICE_P,
  CHOICE_R,
  CHOICE_S
} p_r_s;

void report(outcome result, p_r_s player_choice, p_r_s machine_choice)
{
  char  *names[] = { "paper",
        "rock",
        "scissors" };

  char  *w_l_t[] = { "You win",
        "I win",
        "A tie" };

  printf("You chose %s, I chose %s, %s.", 
          names[player_choice], 
          names[machine_choice], 
          w_l_t[result]);
}

int main(void)
{
  report(WIN, CHOICE_P, CHOICE_R);

  return(0);
}