Need Help With EOF

Can anyone tell me why the EOF (allowing the user to enter F6 or Ctrl Z) may not be working for me? I have a loop running "while(input != EOF)". Any help is greatly appreciated.

I can't tell without seeing more code, it could be that you're trying to read characters and your input variable is declared as char. Since EOF has a value that can't be held by char you would need to use int instead.

Post your code and I'll be able to tell you more

-Prelude

Below is my code from main, I have functions below it that I did not copy here, but this will show you what I am trying to do. I appreciate the help!

//Function Prototypes
void display_header();

int main()
{

//Declare variables
char input;
char operation;
double num1;
double num2;
double result;

//Prototype functions
double product(double, double);
double quotient(double, double);
double sum(double, double);
double difference(double, double);

//Call function
display_header();

//Prompt user to begin
printf("Press enter to begin the program.");
fflush(stdin);
scanf("%c", &input);
fflush(stdin);

while (input != EOF)
{

//Clear screen
system("cls");

//Prompt user for numbers
printf("Enter your first number: ");
scanf("%lf", &num1);
fflush(stdin);
printf("Enter your second number: ");
scanf("%lf", &num2);
fflush(stdin);

//Clear screen
system("cls");

//Prompt user for operation
printf("Choose:\n");
printf("'*' for the product\n");
printf("'/' for the quotient\n");
printf("'+' for the sum\n");
printf("'-' for the difference\n\n");
printf("What operation would you like to perform: ");
fflush(stdin);
scanf("%c", &operation);

//Evaluate operation chosen and call appropriate function
if (operation == '*')
result = product(num1, num2);
else if (operation == '/')
result = quotient(num1, num2);
else if (operation == '+')
result = sum(num1, num2);
else if (operation == '-')
result = difference(num1, num2);
else
printf("Invalid choice!\n\n");

//Prompt user to continue
printf("Press enter to continue program.");
fflush(stdin);
scanf("%c", &input);
}

return 0;
}

>char input;
change that to
int input;
and you should be able to use EOF. EOF is a value too big for a char, so to test for it you need to use an int. It's a tough bug to find unless you know what you're looking for. Kinda goofy, but that's life

-Prelude