correct way to call function through function pointer

Hi,
I'm reading one article about function pointers and I found this simple code:

Code:

#include <stdio.h>

typedef int (*pFunc) (int, int);
int sum (int, int);
int diff (int, int);

int main ( void )
{
	pFunc pfArr[2];

	pfArr[0] =  &sum; /* correct way*/
	/*pfArr[0] =  sum; Possible incorrect way ???*/ 
	pfArr[1] = &diff;

	printf("%d",pfArr[0](2,3));
	printf("%d",(*pfArr[0])(2,3)); /*correct way*/

	return 0;
}

int sum (int a, int b)
{
	return a + b;
}

int diff (int a, int b)
{
	return a - b;
}

I read there about "correct ways" to call function through function pointer.

I tried both solutions and both works fine.

Code:

printf("%d",pfArr[0](2,3));
printf("%d",(*pfArr[0])(2,3)); /*correct way*/

What I'm not sure is whether both solutions are valid according to the Standard. Please, can you comment this

Thanks

- Micko

http://www.eskimo.com/~scs/C-faq/q4.12.html
They're both valid - though I prefer the decluttered versions using no &*()

Thank you master Salem!