Thread: Ok I'm stuck with a double to float error

Here's the snippet of code that I'm having problems with:

Code:

               

                int            customernumber;
	float	waterlevel;
	float	previouslevel;
	float	totalwater;
	float	totalbill;
	float	amountowed;


	printf("Enter customer number\n" );

	scanf( "%d" ,  &customernumber );

	printf("Enter current water level\n" );

	scanf("%f" , &waterlevel );

	printf("Enter previous water level\n" );

	scanf("%f", &previouslevel );

	totalwater = waterlevel - previouslevel;

	totalbill = 30 + (totalwater/1000  * .55);

	amountowed = totalbill;

I keep getting this warning "conversion from double to float, possible loss of data" for this line

totalbill = 30 + (totalwater/1000 * .55);

I dont understand what it could mean, everything is declared as float ( I, obviously, made sure of that), if anyone has any idea what's wrong with this line I would really appreciate it if ya could share it with me.
Thank you very much.

.55 by itself is a double constant.
Since the rest of the expression is float, I think it's this one which making the whole of the right hand side into a double expression.

So when you perform the assignment, the now double expression on the right is being converted to a float.

.55F is the way to define a float constant.