Thread: command line arguments on Solaris 7

I have a simple program as follows:

#include <stdio.h>

int main(int argc, char *argv[])
{
int x;

for (x=0; x<argc; x++)
printf("arg0=%s", argv[x]);

exit(0);
}

If I compile and run on windows when I pass parameters they display, however, they do not display when I compile and run on Solaris 7 using gcc. If I print argc, it equals 0 even if I pass in values. Is there something I'm missing on unix?

Thanks,

Todd Hahn.
[email protected]

Output isn't always flushed unless you send in the newline charecter or you use fflush(stdout). Also to use the exit
function call I think you are supposed to #include <stdlib.h>

Code:

#include <stdio.h> 

int main(int argc, char *argv[]) 
{ 
     int x; 

     for (x=0; x<argc; x++) 
           printf("arg0=%s\n", argv[x]); 

     return 0;
}