Thread: Printing Hex Value of a char

I want to see the Hex representation of an 8 character long aray of char. The value printed is not correct. I'm not really sure on the syntax associated with printing Hex notation.

Code:

# include <stdio.h>

int
main ()
{
	char Name[8];

	printf("Enter an 8 letter name:\n\n");

	scanf("%s", &Name);

	printf("name entered: %s\n\n", Name);
	printf("name entered in Hex: %08x\n\n", Name);

	return 0;
}

Thanks,

try:

Code:

# include <stdio.h>

int
main ()
{
	char Name[9]={0x0};
    char *p=NULL;
	printf("Enter an 8 letter name:\n\n");

	fgets(Name, sizeof(Name),stdin);

	printf("name entered: %s\n\n", Name);
	printf("name entered in Hex:");
	for(p=Name;*p && *p>' ';p++)
	{
	    printf("%02x",*p);
	}
    printf("\n");
	return 0;
}

Originally Posted by swoopy

Try this.

Code:

#include <stdio.h>

int main()
{
	char Name[9];

	printf("Enter an 8 letter name:\n\n");

	scanf("%s", Name);

	printf("name entered: %s\n\n", Name);
	printf("name entered in Hex: %08x %08x\n\n", *(int *)Name, *(int *)(Name+4));

	return 0;
}

this code reverses the characters somehow. It prints the first 4 in reverse order and then the next 4 in reverse, but fill the empty array space with CC INSTEAD OF 20.

I can print it one byte at a time. That seems to work. But I just did that by trial and error, to get the right format.
Could someone tell me what is the proper format for ptinting the hex. What is put in the SOMETHING %SOMETHINGx and how deos it effect the ptintout?

Yep, that's how I wrote my code, in a loop. Thanks lot.

A.