Thread: Problem displaying characters

I was trying to write a program that counts each occurrence of a character in a given array of characters...

Code:

#include <stdio.h>
#include <ctype.h>

int main(void)
{
	int c;
	int counter[256 + 1] = {0};

	printf("Type your name followed by #: ");
	while((c = getchar()) != '#')
	{
		if(c == ' ' || c == '\n' || c == '\t')
			continue;

		++counter[tolower(c)];
	}

	for(c = 0; c < 256; c++) {
		if(counter[c] > 0)
			printf("%c = %d\n", counter[c], counter[c]);
	}

	printf("\n");

	return 0;
}

It seems to be counting the characters correctly but take a look at what it displays when I type, let's say, Max Payne:
Type your name followed by #: Max Payne#
☻ = 2
☺ = 1
☺ = 1
☺ = 1
☺ = 1
☺ = 1
☺ = 1

Can someone help me fix this? Thanks.

Code:

#include <stdio.h>
#include <ctype.h>

int main(void)
{
	int c;
	int counter[256 + 1] = {0};

	printf("Type your name followed by #: ");
	while((c = getchar()) != '#')
	{
		if(c == ' ' || c == '\n' || c == '\t')
			continue;

		++counter[tolower(c)];
	}

	for(c = 0; c < 256; c++) {
		if(counter[c] > 0)
			printf("%c = %d\n", c, counter[c]);
	}

	printf("\n");

	return 0;
}

I have to pay more attention! Thanks.