I have stumbeled on a little problem trying to make a simple rpn calculator.Code:#include<stdio.h> #include<stdlib.h> #include<ctype.h> #include<string.h> void help(void); float sum(float plus[]); int operacija(char *arg); int main(int argc, char *argv[]) { int i; int j=0; int z=0; int st_stevk=0; float sklad[20]={0.}; float plus[20]={0.}; float minus[20]={0.}; float rez_plus=0; float rez_vsota; float rez_produkt; float rez_temp1; if(argc<4) { help(); exit(EXIT_FAILURE); } for(i=1;i<argc;i++) { if(atof(argv[i])>=0.001&&atof(argv[i])<=9999.999) { sklad[j]=atof(argv[i]); j++; st_stevk++; continue; } if(operacija(argv[i])) { z=j-st_stevk; switch(*argv[i]) { //ascii kode od operatorjev case '+': for(i=0;i<st_stevk;i++) { plus[i]=sklad[z]; z++; } break; case '-': for(i=0;i<st_stevk;i++) { minus[i]=sklad[z]; z++; } break; default: break; } rez_plus=sum(plus); printf("%f\n",sum(plus)); } st_stevk=0; } return 0; } void help(void) { printf("\n"); printf("%s","Vpisati moras vsaj tri argumente!\nPrimer: ./sedma 3 4 +, pri tem pa\n"); printf("%s", "mora biti operator vedno za zadnjim\n"); printf("%s","operandom, ki ga operacija zajema\n"); } float sum(float plus[]) { int i; float rez=0; for(i=0;i<20;i++) { rez=rez + plus[i]; } return rez; } float sub(float minus[])// dont bother this method,ill change it { int i=0; int j=i+1; float rez=minus[i]-minus[j]; int z=i+2; while(isdigit(minus[i])) { rez=rez-minus[z]; i++; z++; } return rez; } int operacija(char *arg) { if ((*arg=='+')||(*arg=='-')) return 1; else return 0; }

A rpn calculator first takes the operands and then the operator. For instance if I would type in (as a command line args-->in my prog) 3 4 + would mean 3+4...and so on. My program isn't finished yet and I have only implemented the plus ('+') operation. But here is the problem. If I type some args...for example

the calculator will sucessfully calculate the sum of this numbers and output it( never mind for 20x time output, I will correct that), but the problem is , what if I want to continue?Code:3.4 4.5 3.4 +Then it would only output the sum of the numbers before the first '+' operator and ignore the others.Code:3.4 4.5 3.4 + 2.3 3.4 5.5 +

Maybe Im doing this completly wrong, but I think that my logic is fine, I just dont know how to put it into practice