dec -> bin -> hex in arrays

This is a discussion on dec -> bin -> hex in arrays within the C Programming forums, part of the General Programming Boards category; I have some numbers stored in a character array. Assume length of 3 arrays is: dec[2]; bin[6]; hex[2]; Now if ...

  1. #1
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    dec -> bin -> hex in arrays

    I have some numbers stored in a character array. Assume length of 3 arrays is:

    dec[2];
    bin[6];
    hex[2];

    Now if I have 34 in the dec array i.e. dec[0]=3 and dec[1]=4, how can I convert this into binary and then into hex to fill the other 2 arrays?

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  3. #3
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    Here's one idea.
    >dec[2];
    First make this long enough so you have can use it as a string. To make room for the string terminator, make it at least three char.
    Code:
    char dec[3]
    Then make dec[2] = '\0'

    Now you can use strtol() to convert this to a long:
    Code:
       long num;
       num = strtol(dec, NULL, 10);
    Now to store in a char array as hex, use sprintf():
    Code:
       sprintf(hex,"%X",num);
    There is no library function to convert to binary. To store it in a char array as binary, so you could use a loop to strip each binary digit.

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