Thread: how to pass a function as a parmeter to a function?

OS: linux
compiler: gcc version 3.3.5 (Debian 1:3.3.5-5)
editor: vi
level: beginner


Hello,

I am working through a tutorial at: http://vergil.chemistry.gatech.edu/r...al/basic2.html, which demonstrates how to pass a function as parameter to a function.

I've tried replicating the method shown, but come up against some problems:

Code:

#include <stdio.h>

int squared(int x){return x*x;};
int cubed(int y ){return y*y*y;};
int result(int F(int))
{

        int a;
        a=F(int);
        return a;
};


int main()
{
        int x = 1;

        for (;x < 10;x++)
        {
                printf("squared%i\t",result(squared(x)));
                printf("cubed%i\t",result(cubed(x)));
        }
        return 0;
}

errors returned compiled with gcc play.c :
play.c: In function `result':
play.c:9: error: parse error before "int"
play.c: In function `main':
play.c:20: warning: passing arg 1 of `result' makes pointer from integer without a cast
play.c:21: warning: passing arg 1 of `result' makes pointer from integer without a cast


I would be grateful if someone could point me in the right direction on how to pass function(s) as parameter(s)

Thanks

Billy

P.S Already googled

Thanks Salem for your time and help!

Regards

Billy