Simple question about pausing program

First off, I just started learning how to use C a few days ago by using a 1988 version of C Primer Plus. I think it's a little outdated, and I'm about to burn this book. But here is my question; I'm trying to get the simple programs in the tutorials to stay open so I can see what is happening ( they close immediately). I found this script (don't even know if it is called a script) on this website:

Code:

#include <stdio.h> 

int main(void)  /*wait for keypress*/
{
  int ch;
  printf ("Press [Enter] to continue");
  while ((ch = getchar()) != '\n' && ch != EOF);
  return(0);
}

it works when this is all that my program consists of, but when I try to add it to a program in one of the tutorials, such as:

Code:

#include <stdio.h> 

int main(void)  /*wait for keypress*/
{
 
float weight, value;
char beep;

beep = '\007';
printf("are you worth your weight in gold?\n");
printf("Please enter your weight in pounds, and we'll see.\n");  
scanf("%f", &weight);
value = 400.0*weight*14.5833;
printf("%cYour weight in gold is worth $%2.2f%c.\n", beep,value,beep);
printf("Your are easily worth that! If gold prices drop, ");
printf("eat more\nto maintain your value.\n");    
    
int ch;
printf ("Press [Enter] to continue");
 while ((ch = getchar()) != '\n' && ch != EOF);
 return(0);
  
 }

it does not ask for me to hit enter, but just closes after running the commands.

Did I enter something wrong?

If anyone helps with this simple problem, I am extremely greatful. I pretty much wasted a night on figuring this out, and I've given up searching for an answer on the web.

By the way, I'm using Dev-C++

Help me overcome! thanks

http://faq.cprogramming.com/cgi-bin/...&id=1043284385

the faq at cprogramming.com is really nice..

Code:

scanf("%f", &weight);

You type a number followed by the enter key, right? The number is converted and the newline is left in the stdin. Without waiting for you to enter anything new, the newline is then consumed here.

Code:

while ((ch = getchar()) != '\n' && ch != EOF);

See also
FAQ > How do I... (Level 2) > Flush the input buffer

A simple method is to just add a "ch= getchar()" line that removes off the extra '\n' from the scanf() input.

Code:

#include <stdio.h> 

int main(void)  /*wait for keypress*/
{
 
	float weight, value;
	char beep;
	int ch;

	beep = '\007';
	printf("are you worth your weight in gold?\n");
	printf("Please enter your weight in pounds, and we'll see.\n");  
	scanf("%f", &weight);
	value = 400.0*weight*14.5833;
	printf("%cYour weight in gold is worth $%2.2f%c.\n", beep,value,beep);
	printf("Your are easily worth that! If gold prices drop, ");
	printf("eat more\nto maintain your value.\n");    

	ch=getchar();    
	printf ("Press [Enter] to continue");
	while ((ch = getchar()) != '\n' && ch != EOF);
	return (0);
}

Your "simple method" breaks if they type anything else other than one character past what you want them to. That's why we tell you to read the FAQ. Or rather, that's why it's been suggested two times already. Well, here's hoping "three times is a charm".

Quzah.

...or just run your program from the command prompt.

i have a long way to go...but these all get me past my problem, so I can continue with the tutorials.

Thanks everyone, I appreciate the help

Truth was I didn't really get how the FAQ code would flush the buffer in his case

Code from the FAQ:

Code:

#include <stdio.h> 

int main(void)
{
  int   ch;
  char  buf[BUFSIZ];
  
  puts("Flushing input");
  
  while ((ch = getchar()) != '\n' && ch != EOF);
  
  printf ("Enter some text: ");
  
  if (fgets(buf, sizeof(buf), stdin))
  {
    printf ("You entered: %s", buf);
  }
  
  return 0;
}

In this case there was nothing in the buffer before the while() loop which meant all it did was discard characters until a new line (or EOF) was reached. Since you stored it in ch, obviously the fgets() won't be effected. Or I'm not seeing something obvious here

Heh never mind I get it now! *smacks head*

dude.its all done.hope it works on Dev C++

Code:

#include <stdio.h> 
#include<dos.h>
int main(void)  /*wait for keypress*/
{
 
float weight, value;
char beep;

beep = '\007';
printf("are you worth your weight in gold?\n");
printf("Please enter your weight in pounds, and we'll see.\n");  
scanf("%f", &weight);
value = 400.0*weight*14.5833;
printf("%cYour weight in gold is worth $%2.2f%c.\n", beep,value,beep);
printf("Your are easily worth that! If gold prices drop, ");
printf("eat more\nto maintain your value.\n");    
    
int ch;
shyam:
printf ("Press [Enter] to continue");
ch=getchar();
 if ((ch = getchar()) != '\n' && ch != EOF)
 {
	 goto shyam;

 }
 else
 {
	goto ram;
 }
ram:
 return(0);
  
 }

please maintain structuring in your code.it will make our job of debugging easier.

What's wrong with System("pause")?
I know some commands aren't portables but... either way can pause the programm... or I miss something?

Well, if you had read the FAQ...

But then, you already answered your own question. Why use a nonportable method when there are portable versions that work just as well?

But then, if you had read the FAQ...

Quzah.

mmm, I did.. but if the program is ment to run only in my machine... and I can support those non-portable... wouldn't be heavy to use them, right?

Do whatever the ........ you want. No one here gives a ......... But when we try to help people, we're not just talking about "my machine". Therefore, we don't post stupid system specific answers when there's a portable option that's just as easy.

Quzah.

So... quzah are you in flame war to me? Talk about free speaking.

You asked what was wrong with system( "pause" ), I told you. You replied that for you you'd use it anyway, I said I didn't care. End of discussion. If you want to carry it further, don't waste space in this thread, PM me.

Quzah.