Scanf()

**robasc** · 03-27-2005

I have a question on another one of my assignments:

Use scanf to store that integer in an unsigned int. Use Printf to display “You entered” and the actual positive integer.

could someone explain how to use scanf a little more for me in a way that I will understand how to use it in my assignment?

**l0cke** · 03-27-2005

[edit]There is a bettter link in the post below.[/edit]

You can use %u with scanf()/printf() to read/print an unsigned int(assuming you know a little bit about scanf()/printf()).

**Bajanine** · 03-27-2005

This example will read in a interger from stdin and store it into a variable at the address of x.

Code:

scanf("%d", &x);

Also this LINK will explain scanf far better than I can

, and it will also explain some of the problems people like me have implementing it!

Wow, beaten again!

**robasc** · 03-27-2005

I am working with scanf and hoping someone can explain what is going on here:

Code:

#include <conio.h>
#include <stdio.h>
typedef unsigned char u_char;
typedef unsigned int u_int;

main(void){
       int a;
       u_int b;
    u_char c;
    float d;
    printf("enter an integer: ");
  
       scanf("%s",&b);
   printf("\nyou entered: ");
   printf("%s\n\n");
   printf("%s in octal is:  ");
   printf("%o");

my code output is
enter an integer

you entered 3

in octal is: 10577560 is this correct?

**Hammer** · 03-27-2005

You need to use the proper format modifier here:
scanf("%s",&b);
b is not a string, so you shouldn't be using %s.

In the printf() statements, you've missed out the variable names.
It should look something like this:
printf("Number: %d\n", mynumber);

**ssharish** · 03-27-2005

compare the code of mine and yours, and check out the syntax error

your code:

Code:

#include <conio.h>
#include <stdio.h>
typedef unsigned char u_char;
typedef unsigned int u_int;

main(void){
       int a;
       u_int b;
    u_char c;
    float d;
    printf("enter an integer: ");
  
       scanf("%s",&b);
   printf("\nyou entered: ");
   printf("%s\n\n");
   printf("%s in octal is:  ");
   printf("%o");

my code

Code:

#include <conio.h>
#include <stdio.h>
typedef unsigned char u_char;
typedef unsigned int u_int;

main(void){
       int a;
       u_int b;
    u_char c;
    float d;
    printf("enter an integer: ");
  
       scanf("%d",&b);
   printf("\nyou entered: ");
   printf("%d\n\n",b);
   printf("%o in octal is:  ",b);

s.s.harish

**robasc** · 03-27-2005

well after running your code everything works fine eccept it does not output the answer for octal.

I did not get any syntax error for either code.

**l0cke** · 03-27-2005

Code:

printf("%u in octal is: %o\n", b, b); /* try this instead */

**ssharish** · 03-27-2005

hey its printing the octal. u might be confused with the format of what we are printing

make it like this

Code:

printf("The octal value of b is %o",b);

s.s.harish

**robasc** · 03-27-2005

Hey guys this is what I came up with after the help from all of you guys.

Code:

#include <conio.h>
#include <stdio.h>
typedef unsigned char u_char;
typedef unsigned int u_int;

main(void){
       int a;
       u_int b;
    u_char c;
    float d;
    printf("enter an integer: ");
  
       scanf("%d",&b);
   printf("\nyou entered: ");
   printf("%d\n\n",b);
   printf("in octal is: %o ",b);
 getch();
}

this is working great!

Thread: Scanf()

Thread Tools

Search Thread

Display

Scanf()

Similar Threads

scanf() consideres useless

Help with a basic scanf procedure.

Odd data entry error, reading an unsigned integer with scanf

Scanf and integer...

scanf - data is "put back" - screws up next scanf