Thread: quicky

  1. #1
    Registered User
    Join Date
    Nov 2001
    Posts
    18

    Talking quicky

    while((a[i].sex != '0') && (a[i].sex != '1'))
    {
    printf("Error, please may you enter 1 for male or 0 for female(person %d)\n", i);
    scanf("%d",&a[i].sex);
    }

    why does this not work if someone enters in 1 / 0 for a[i].sex

  2. #2
    Registered User
    Join Date
    Nov 2001
    Posts
    18
    sorry ignore I am a dumb git made a typo

  3. #3
    Unregistered
    Guest
    while((a[i].sex != '0') && (a[i].sex != '1'))

    That won't work because you're using the characters 0 and 1, which are completely different in integer value from the integers 0 and 1.

    while( ( a[i].sex != 0 ) && ( a[i].sex != 1) ) {

    -Prelude

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