Assinging value to *pointer

[Brigs76]

Hi,

I am trying to write a program to convert Hex to Bin. I found a useful piece of code on these forums to do just that except I have one problem. I want the user to enter a hex value, not have it defined:

int funcHextoBin()
{
char *userhexd;
//char *userhexd = "92C3";
char hex[] = "0123456789ABCDEF";
char *bin[] = { "0000", "0001", "0010", "0011", "0100", "0101",
                  "0110", "0111", "1000", "1001", "1010", "1011",
                  "1100", "1101", "1110", "1111" };

printf("Hex to Bin!\n");
printf("Enter a Hexadecimal: \n");
scanf("%s", userhex);
//printf("You entered: %s\n", userhex);

*userhexd = &userhex;

while(*userhexd)
  {
    printf("%s", bin[strchr(hex, *userhexd)-hex]);
    userhexd++;
  }
  putchar('\n');

system("PAUSE");
return 0;
}

As you can see the original code had *userhexd with a predefiend value. All I want to change is so that the user enters a vlue. However right now the progrma crashes with a warning "assingment makes integer from pointer without a cast" I believe the problem is "*userhexd = &userhex;" Is there any special way I can assign the user's value to *userhexd?

Thanks.

[Dave_Sinkula]

To get userhexd into the function, pass it as a parameter. Obtain your string in the calling routine and pass this string to the function. Other than that, try to leave the function as you found it.

[Brigs76]

Can you please give an example of how to do that? I am relly new to C programming.

Many thanks

[Dave_Sinkula]

void funcHextoBin ( const char *userhexd )
{
   /* stuff */
}