I have some instrucions here to write a program and I have no clue where to start.
here are the instructions:
Write a C Program to generate output given by a3q3.exe. You will need to use printf with format specifier %c to print ASCII values of 218,196,191, 179, 192 and 217.
please look at the example.
Declare some int variables and assign the numeric values that you have, and then print them out using the %c specifier. Another solution which is easier i guess is to use putchar.
When no one helps you out. Call google();
Do you mean like this
Code:#include <conio.h> #include <stdio.h> #define int 218,196,191, 179, 192,217; main(void){ printf(""); printf(""); getche(); }
Last edited by robasc; 03-06-2005 at 05:35 PM.
Umm. No.
You've already been given the answer to this. Just use printf("%c",<value>); where <value> is the int value you want to print and voila, you're on your way.
ok like this
Code:#include <conio.h> #include <stdio.h> main(void){ printf("%c,217"); printf(""); getche(); }
nope thats not a solution either, you have not declared a variable or intialized it with a value.
to declare a variable you do something like this
to initialized the variable you do something like this,Code:int num1;
to print it out you do something like this.Code:num1 = 217;
Code:printf("the ASCII value of 217 is%c \n", num1);
When no one helps you out. Call google();
when you run this code above it print an H. I thought that the value of 218 should look like
an upside down L?
it is an upside down L.
my output for 218. is
Code:The ascii value of 218 is: ┌. Press any key to continue
When no one helps you out. Call google();
isnt this assignment supposed to print some assigned ascii code to make the above example?
You just use the numeric value of 218 to print the ascii code that looks like an upside down L. show the code where you getting H on your output, maybe you doing something wrong.
When no one helps you out. Call google();
ok this is the only way I could compile this to run it:
Notice on the printf statement I made a small change. My compiler would not compile it =, I keep getting compiler errorsCode:#include <conio.h> #include <stdio.h> main(void){ int number1; number1 = 218; printf("the ASCII value of 218 is%c \n, num1"); getche(); }
such as:
Compiler: Default compiler
Executing gcc.exe...
gcc.exe "C:\Documents and Settings\dustin\My Documents\computer programming class\ass3,q3.c" -o "C:\Documents and Settings\dustin\My Documents\computer programming class\ass3,q3.exe" -I"C:\Dev-Cpp\include" -L"C:\Dev-Cpp\lib"
C:\Documents and Settings\dustin\My Documents\computer programming class\ass3,q3.c: In function `main':
C:\Documents and Settings\dustin\My Documents\computer programming class\ass3,q3.c:7: error: `num1' undeclared (first use in this function)
C:\Documents and Settings\dustin\My Documents\computer programming class\ass3,q3.c:7: error: (Each undeclared identifier is reported only once
C:\Documents and Settings\dustin\My Documents\computer programming class\ass3,q3.c:7: error: for each function it appears in.)
Execution terminated
My output reads: The ascII value of 217 isH
notice your printf statement and notice the printf statement i posted as an example, you see the difference?
When no one helps you out. Call google();
I am sure that the problem lies in the printf statement;however,
it will not compile the way you wrote it.
what else am I doing wrong?Code:#include <conio.h> #include <stdio.h> main(void){ int number1; number1 = 218; printf("the ASCII value of 217 is%c \n", num1); getche(); }
You refer to num1 in your printf statement. You haven't defined num1. Define it, or change the variable that you're referring to.
