(int*) question

This is a discussion on (int*) question within the C Programming forums, part of the General Programming Boards category; abc = (int *)&abc + 2; does the (int*) turn the address of abc+2 into a pointer, if not, can ...

  1. #1
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    Question (int*) question

    abc = (int *)&abc + 2;


    does the (int*) turn the address of abc+2 into a pointer, if not, can someone explain it.

  2. #2
    Just Lurking Dave_Sinkula's Avatar
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    >does the (int*) turn the address of abc+2 into a pointer

    No. The address of abc, &abc, is resolved into a pointer (of whatever type abc is). The cast, (int*), converts that resulting pointer to a pointer to an int. The addition of 2 results in a pointer that is 2 * sizeof(int) bytes from &abc. This is the value that is then assigned to abc, which one might presume to be a pointer to int.

    Or, abc is assigned a value which is a pointer to a location 2 integers beyond the location of abc itself.
    7. It is easier to write an incorrect program than understand a correct one.
    40. There are two ways to write error-free programs; only the third one works.*

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