Question on Structures in C - a different one

I have executed the following program

Code:

#include <stdio.h>
struct test
{
     int a,b,c;
}test;
struct test testObj;

main()
{
    testObj.a = 100;
    testObj.b = 200;
    testObj.c = 300;
    printf("%d %d %d \n", testObj, testObj, testObj);
    return 0;
}

The output was - 100 200 300.

I was expecting ouput as - 100 100 100.

Can anyone explain why the output is like this?
I tried looking into the assembly code for the same program and I found that before a call to printf the elements are pushed into the stack as following
testobj+8
testobj+4
testobj

When I replaced the printf statement with the following one

Code:

    printf("%d %d %d \n", testObj, testObj, testObj.b);

still I got the same o/p (even the assembly was also the same).

Is it related to the compiler?
Pointers please.....


Gvs

No, it's related to your code being wrong.

%d expects an integer (testObj.a) not a copy of a structure (testObj)

That it apparently prints anything remotely sensible is luck, not judgement.

I suggest you get a copy of gcc (or one of it's wrapper IDEs like DEV-C++) and use the -Wall compiler option to debug your mis-use of printf.

i run the codes get the same results
can you tell why ???

Try reading once in a while, and stop with the nonsensical posting.

Quzah.

Originally Posted by pacific

i run the codes get the same results
can you tell why ???

because

Code:

printf("%d %d %d \n", testObj, testObj, testObj);

every parameter passed to printf, even though they are not ints as they should be, the same 4 bytes (or sizeof(int)) is being printed from the begining of the structure.

Don't waste your time sand_man , he's just posting to raise his post count.

a question with pointers
help with using printf()