Read

[Unregistered]

Hi i am writing this function to read a txt file where there's two
line of text

Name Surname
ID_NUMBER

and usig the following file_read () i want to display it on the screen and the following is the code that i am using any idea on why is not working ?

file_read()
{
FILE *fp;

char Name[30];

fp = fopen("id.txt","r");

if ((fp = fopen("id.txt","r")) == NULL)

{
printf("Unabale to open id.txt file \n");
exit(1);
}

while(fgets,(Name,30,fp) != NULL){

}
fclose(fp);
}


Thank you !

[C_Coder]

fp = fopen("id.txt","r");

if ((fp = fopen("id.txt","r")) == NULL)

{
printf("Unabale to open id.txt file \n");
exit(1);
}

You open the file with the first line and then in your if statement you try to open it again and as the file is already open this will produce a NULL response every time, remove the first line.

while(fgets,(Name,30,fp) != NULL){

lose the comma which is after fgets and before the first (

[Unregistered]

Thanx C_Coder it compiles fine and i now have another problem is not displaying the content of the file.




#include <stdio.h>
#include <stdlib.h>
#include <string.h>


main()

{

FILE *fp;


char Name[30];




fp = fopen("a:/id.txt","r");

if ((fp = fopen("a:/id.txt","r")) == NULL)

{
printf("Unabale to open id.txt file \n");
exit(1);
}

while(fgets(Name,30,fp) != NULL){

}

fclose(fp);
}

[C_Coder]

Mmmmm you still have 2 fopen statements, Im sure that wont work remove the first one. as for not displaying the contents of the file you need to add a line in your loop to print them to the screen.

while(fgets(Name,30,fp) != NULL){ 
     printf("%s", Name);
}

[Unregistered]

Thanx C_Coder it works i didnt noticed that i wrote fopen twice..ohh am glad

sorry man I have one more question if you dont mind ! :-).

what's the best way of starting this program to make it read the ID and generate a dynamic linked list, where each node of the linked list would contain a single integer from the ID.



Thanx again.