Thread: is this for loop correct?

Code:

{
    double k;
    double sumsqrd;
    sumsqrd = 0;

    for (k =0; k <= 5; k++); {

        sumsqrd =pow(k,2);
    }    
    {
         sumsqrd +=numbers[k]
    }
    return sumsqrd;
}

what im trying to do is , having 5 numbers, square each of them and then add their squares.

its part of a proptotype thats why the braces are there, i have edit the code to include pow(), the 2nd pair of braces is there so i dont get confused lol

Code:

    double k;
    double sum;
    double sumsqrd;

    sumsqrd = 0;
    sum =  0;
for (k =0; k <= 5; k++); 
{
	sum =+numbers[k];
}
     
    return sumsqrd=pow(sum,2);
}

figured it out correct?

i havent declared the array here, but the array is declared in the program. this is part of a prototype that adds and squares the values in the array.

Your code:

Code:

for (k =0; k <= 5; k++); 
{
    sum =+numbers[k];
}

Your for() loop is only incrementing k 6 times because you have that ; stuck on the end. But it looks like you want to execute what's in the following code block (which has the wrong syntax) 6 times instead.

yeah that semicolon is a typo, thanks for pointing it out.

Originally Posted by InvariantLoop

what im trying to do is , having 5 numbers, square each of them and then add their squares.

Code:

#include <stdio.h>

int sum_of_squares ( int array[], int size )
{
   int i, sum = 0;
   for ( i = 0; i < size; ++i )
   {
      sum += array[i] * array[i];
   }
   return sum;
}

int main(void)
{
   int array[] = {1,2,3,4,5};
   int ssq = sum_of_squares ( array, sizeof array / sizeof array[0] );
   printf ( "ssq = %d\n", ssq );
   return 0;
}

/* my output
ssq = 55
*/

thanks for the input Dave and for another way to doing things, i have gotten passed this issue. what i did is use a for loop to square the values and another nested for loop to add their squares.