Convert char string to decimal equivalent (eg: a = chr(97))...

Hi, I'm programming in C, on mandrake linux. I was wondering if there's any easy way to convert a string of letters into their 'character code' (or decimal) equivalent? I know of one long way round, which would be to make a list of all of the characters and numbers equivalent to each other, then call that list for reference every time I wish to convert a character, but i'm sure it can be done another way.

Code:

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>
main(int argc, char *argv[])
{
    //execl("/usr/bin/konqueror", " cnn.com", (char *) 0);
    
    //define char variable for the app name.
    char ichar[1024] = "konqueror ";
    //define a char variable for the command to be converted.
    char arbit[40] = "dir";
    
    //check we have 4 arguments in total.
    if (argc != 4)
    {
        printf("Incorrect usage!\n");
        return 0;
    }
    
    
    //add argv[1] to the end of the ichar string.
    strcat (ichar, argv[1]);
    //run the command.
    system(ichar);

    
    //convert string to decimal.
    /*THE FOLLOWING DOESNT WORK
    char my_string[] = "a";
    printf("%s = %d\n", my_string);
    printf ("%s\n", ichar);
    SO IT'S COMMENTED OUT*/

return 0;
}

Any ideas? I heard atoi() converts a string, or character into an integer, but whatever character, or string i give it, it keeps returning 0, not the decimal equivalent.

Any help would be much appreciated.

Thanks.

Blueprint.

So are you just trying to convert a character to its ASCII value? If so, then just do:

Code:

char somechar = 'a';
int charval = somechar;
printf("%c = %d\n",somechar,charval);

To do that for an entire string, just loop through the above code for each char in the string. If you are trying to convert a string representation of a number into an integer, then you use atoi().

Code:

char str[] = "1234";
int i = atoi(str);
printf("%d\n",i);

Hi,

I just want to say THANK YOU! That particular question's answer isn't easily found on the internet!!! The first code example was the one I was after:

Code:

char somechar = 'a';
int charval = somechar;
printf("%c = %d\n",somechar,charval);

The atoi() just kept returning the integer 0 for every character I passed through it.

Such simple methods are so easily overlooked!

Thanks again!

Blueprint.

I send out the string "FFFD" trying to convert it to hits integer. How do I go about doing that?

Is this right?

Code:

unsigned int DumpMode(unsigned char *start_addr,unsigned char *end_addr)
{
long pp;
unsigned int putin[15];

	 pp = atol(end_addr);
	 printf("%ld",pp);
	 return 0;
}

Probably because "FFFD" is not a number.


Quzah.

So what would be the best way to convert the Hex string into a number?

Well, prefix it with "0x" and use strtol, or do it by hand. Convert the letter or number yourself . Either way works.


Quzah.

Thx quzah, that really helps a lot

Another one.

Code:

#include <stdio.h>

void foo(const char *text)
{
   unsigned int value;
   if ( sscanf(text, "%x", &value) == 1 )
   {
      printf("value = %u\n", value);
   }
}

int main(void)
{
   foo("FFFD");
   return 0;
}

/* my output
value = 65533
*/

Also helpful. Appreciate it

All you seem to want is something like this?

Code:

int main(int argc, char *argv[]) {
	const char* rawr = "abcdefg";
	for(int i = 0; i < strlen(rawr); i++)
		printf("%d ", rawr[i]);
	return 0;
}

Just to see the ASCII codes of characters? Sorry if I misread your question. You didn't seem interested in atoi or anything, I think you mentioned you just wanted to see the codes.