For Loop - Need desparate help!

This is a discussion on For Loop - Need desparate help! within the C Programming forums, part of the General Programming Boards category; I have been struggling to get this to work and need help deperately - can someone take a look and ...

  1. #1
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    Angry For Loop - Need desparate help!

    I have been struggling to get this to work and need help deperately - can someone take a look and help me?


    #include <stdio.h>

    main()
    {
    int num_employees, /* Number of employees */
    response, /* Response of 1 Yes for 0 for No */
    upper_limit; /* tests # of employees entered */
    double wage_rate, /* Hourly Pay Rate */
    hours_worked, /* Hours worked */
    weekly_pay, /* Weekly pay for employee */
    total_weekly_pay; /* Total weekly pay for employees */

    /* Ask for an employee */

    printf("\nDo you want to process an employee? ");
    printf("\nEnter 1 for Yes or 0 for No: ");
    scanf("\n%d", &response);

    printf("\nPlease enter wage rate for current employee: ");
    scanf("%lf", &wage_rate);
    printf("\nPlease enter number of hours worked: ");
    scanf("%lf", &hours_worked);

    /* For Loop, Calculate and Display */

    for (num_employees = 1; num_employees <= upper_limit; ++num_employees)
    {
    weekly_pay = wage_rate * hours_worked;
    printf("\nWeekly Pay for this Employee: %.2f\n",weekly_pay);

    total_weekly_pay += weekly_pay;
    }

    /* Ask for another employee */

    printf("\nDo you want to process another employee? ");
    printf("\nEnter 1 for Yes or 0 for No: ");
    scanf("\n%d", &response);

    printf("\nThe Total Weekly Pay for %d employees is %.2f\n\n",
    num_employees, total_weekly_pay);
    }


    The problem I am having is that it totally skips the loop.

    Thanks!

  2. #2
    Nosepicker DrakkenKorin's Avatar
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    It may be skipping the loop becuase upper_limit has never been initialized, but then again, it may not be.

    A few other things I noticed:

    Code:
     printf("\nDo you want to process an employee? ");
    printf("\nEnter 1 for Yes or 0 for No: ");
    scanf("\n%d", &response);
    you never check to see if they even want to process any employees. A simple if will fix that (for both tests).

    Other than that, the code seems fine to me, of course it's passed my bed time and I don't have my glasses on.

    Another thing, should use int main(), instead of just plain old main(). The very last statment should be return0
    DrakkenKorin

    Get off my Intarweb!!!!

  3. #3
    ATH0 quzah's Avatar
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    for (num_employees = 1; num_employees <= upper_limit; ++num_employees)
    Your problem is probably the fact that you never give "upper_limit" any value. What's "upper_limit" supposed to be?

    [edit: ya beat me to it!]

    Quzah.
    Hope is the first step on the road to disappointment.

  4. #4
    Registered User mattz's Avatar
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    I am having similar issues with for loops.
    Wish I could help.

  5. #5
    Registered User mattz's Avatar
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    printf("\nDo you want to process another employee? ");
    printf("\nEnter 1 for Yes or 0 for No: ");
    scanf("\n%d", &response);

    what happens here to response if the user enters 0 or 1 ...don't see any statements referring to response?

  6. #6
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    Code:
    #include "stdio.h"
    
    #define YES    1
    #define NO     0  // not used
    
    int main()
    {
    	int num_employees = 0, response;
    	double wage_rate, hours_worked, weekly_pay = 0, total_weekly_pay = 0;
    	
    	while(true){
    		// Process an employee?
    		printf("\nDo you want to process an employee?[1/0] ");
    		scanf("%d", &response);
    		
    		if(response == YES){
    			// wage rate?
    			printf("\nWage rate for current employee: $");
    			scanf("%lf", &wage_rate);
    			
    			// hours worked?
    			printf("Number of hours worked: ");
    			scanf("%lf", &hours_worked);
    			
    			// calculate/display
    			weekly_pay = wage_rate * hours_worked;
    			printf("Weekly pay for current employee: $%.2f\n",weekly_pay);
    			
    			total_weekly_pay += weekly_pay; num_employees++;
    		}
    		else
    		        break;
    	}
    	
    	// display total pay for all employees
    	printf("\nThe Total Weekly Pay for %d employees is $%.2f\n\n", 
    		                         num_employees, total_weekly_pay);
    	                            
    	return 0;
    }
    try it.

  7. #7
    Registered User mattz's Avatar
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    I get the following error during compile:

    d:\code\funcode\fcode.c(11) : error C2065: 'true' : undeclared identifier

  8. #8
    and the hat of wrongness Salem's Avatar
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    true is not a C keyword - it's C++

    Substitute the value 1 for true

    So
    while ( 1 )

  9. #9
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    Smile Specifically: For Loop

    knave or anyone else that wants to help:

    your result works but I need to stick with the for loop because that is what they are requesting. Its actually a 3 part question. My While loop worked, the do-While is almost there but the for loop is driving me mad...

    can you give me input on how I set it up with the for loop? I have now inicialized the upper_limit to 20 but now my output loops 21 times and goes straight to the "weekly total for 21 employees is: $XXXX.XX.

    Thanks...

  10. #10
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    Guest
    Yup. Easy fix:

    for( x = 0; x < 20; x++ )

    Or...

    for( x = 1; x < 21; x++ )

    Your problem is that you're doing "<=" which means it also executes when it is 20 or 21 respectively.

    Quick example:

    for( x = 0; x <=1; x++) printf("I print twice!");

    It prints once when x is zero, and once when x is one, because in both cases, x is LESS THAN OR EQUAL TO, not just LESS THAN.

    Quzah.

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