Thread: printf() error

Code:

void jogo()
{
    
    system ("cls");
    printf("Jogo Matarrocha\n\n");
    printf("Introduza o seu nome: ");
    scanf("%s",&nome);
    for (dinheiro=300;dinheiro>0;)
    {
        
        printf("O que deseja faxer?\n");
        printf("a: Apostar\nb: Comprar\nc: Sair\n\n");     
        scanf("%c",&a);
        
        switch (a)
{
case 'a' : apost();
case 'b' : comprar();
case 'c' : printf("");
}       
}    
    printf("Perdeu");
    getch();
    
}

Code:

 void apost()
{
    fflush(stdin);
    printf("Senhor %s... Tem %d euros\n",nome,dinheiro);
        printf("Quanto deseja apostar?\n");
        scanf("%d",&aposta);
        ra = ( rand() % (1 - 0 + 1) + 0 );        
        if (ra==0)
        {
        printf("Parabens ganhou %d euros\n",aposta);
        dinheiro=dinheiro+aposta;
        }    
        if (ra==1) 
        {
        printf("Perdeu %d euros\n",aposta);
        dinheiro=dinheiro-aposta;
        }
        
}

when i run a program with this function.. it dysplay 2 times the:

Code:

  printf("Senhor %s... Tem %d euros\n",nome,dinheiro);
        printf("Quanto deseja apostar?\n");
scanf("%d",&aposta);

and only scan 1 time

Well there are several things wrong with the code as it stands.
1) where are all the variables declared? I mean a lot of them should be local (for example loop control variables), but everything seems to be global.
2) why are no parameters being passed between functions.
3) fflush(stdin); is undefined - it might work for you, but it doesn't work for me. This topic is discussed in the FAQ.
4) scanf() is a tricky function, and %c as a conversion makes it especially difficult.
5) case 'a' : apost();
There are no break statements, so typing in 'a' causes all 3 functions to be called.
6. ra = ( rand() % (1 - 0 + 1) + 0 );
This seems an overly complex way of saying ra = ( rand() % 2 );

*CLOSED*