error on working with files

Hello guys. Sorry for disturbing but i do need some help.
I maked a simple program that reads from a file which looks like this:

Code:

---

#include <stdio.h>

int main(){
    FILE *fin;
    int var[10000][7],n,i,j;
    if((fin=fopen("var.in","r+"))==NULL)
        exit(1);
    fscanf(fin,"%d",&n);
    printf ("%d\n",n);
    for(i=1;i<=n;i++){
        for(j=1;j<7;j++){
            fscanf(fin,"%d",((var+i)+j));
            }
    }
    for(i=1;i<=n;i++){
        for(j=1;j<7;j++){
            printf("%d ",*(*(var+i)+j));
            }
        printf("\n");
    }           
    return 0;
    fclose(fin);
}

---

and the file var.in looks like this:

Code:

---

2
1 3 4 5 6 7
6 4 6 4 3 2

---

My program prints this:

Code:

---

2
0 0 0 0 0 0
0 0 0 0 0 0

---

Could anyone help me, and explain why is this happening? instead of that 0's should be the values on the second and third line of the file.

Thanks a lot!
Regards,
Victor

Well writing

Code:

---

int status = fscanf(fin,"%d", &var[i][j] );

---

instead of

Code:

---

fscanf(fin,"%d",((var+i)+j));

---

would help clarify things.

Do the same on the printf, use array notation and not pointer arithmetic.

Checking the return result of fscanf for errors as well would be a good idea.

Code:

---

    return 0;
    fclose(fin);

---

How often do you think that fclose() will be called?

Ok, i had a pointer arithmetic problem indeed. Thanks Salem, and ofcourse thanks itsme86 :).

But why didn't my program worked with pointer notation?

> But why didn't my program worked with pointer notation?
Because you got it wrong.

fscanf(fin,"%d",(*(var+i)+j));
works for me

> for(j=1;j<7;j++){
You do know that arrays start at index 0 and not 1 right?

Damnn.... now i saw the mistake i have made. stupid me... sorry :(

Yes, I do know that arrays start at index 0 and not at 1 but in my problem was convenient to start from 1 :D