Thread: Floats

  1. #1
    Registered User
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    Oct 2001
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    15

    Question Floats

    I have a value assigned to a variable called x (float) of 12.56.
    I have another int variable called y. If I want to output 12 (from the 12.56) i can do:

    y = x;
    printf("%d", y); /*truncates the 12.56 and out puts 12 only*/

    Any ideas how I just output the .56 of the 12.56??

  2. #2
    Registered User Strider's Avatar
    Join Date
    Aug 2001
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    Here is a sample of what you could do:
    Code:
    #include <stdio.h> 
    
    int main() 
    { 
        float x = 12.56f;
        int y;
    
        y = (int)x;
        printf("%d plus %.2f equals %.2f\n", y, (x - y), x);
        /* %.2f will display float values with decimal precision of 2. */
    
        return 0;
    }
    David
    One Ring to rule them all, One Ring to find them,
    One Ring to bring them all and in the darkness bind them
    In the Land of Mordor where the Shadows lie.

  3. #3
    Confused Magos's Avatar
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    float Var=12.56;
    printf("%f", Var-(float)((int)Var) );

    I just made that up, not sure if it works however. This is what it does:

    (int)Var //12.56 --> 12

    (float)(...) //(int)12 --> (float)12

    Var - (...) //12.56 - 12 --> 0.56
    MagosX.com

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