bitwise IF statement

Hello!

I have a simple question here:
How does an IF statement react on bitwise commands like this:
a = 0x07;
b = 0x02;

if(a&b)
DoSomething();

Is the IF statement TRUE or FALSE?

Tnx
/D
:confused:

this statement would be true:
since 0x7 = 0111 bin
and 0x2 = 0010 bin

-> the result of the & operation is 0x2
and this is not 0, so its True :)

I'd say it returns true.

0x07 in binary is 111 and 0x02 is 010, so when it does the math

Code:

---

  111
& 010
----------
  010

---

which gives 2 as a result anyway.

EDIT: Damn you IceBall, you beat me!

Quote:

---

Originally Posted by DeeAitch

How does an IF statement react on bitwise commands like this:

Code:

---

  a = 0x07;
  b = 0x02;

  if (a & b)
      DoSomething();

---

Is the IF statement TRUE or FALSE?

---

There is no 'IF' in C. Maybe you meant 'if'.

There is no 'command' in C, but statements, operators, expressions, functions...

A C expression returns 0 or 1, not TRUE/FALSE.

Simple question of boolean logic. What is the AND truth table, what is the result of 0x07 AND 0x02 ?

Code:

---

      a = 0000 0111
      b = 0000 0010
a AND b = ???? ????

---

Shake your brain, it helps...