Thread: Pass an entire struct

Hey guys ive search around on previous, and found some similar post but not exactly. Im trying to pass an entire array of structs to a function. The structure is declared as a local varriable in main ( my professor has a problem with global varriables) and it needs to be pass to a function.

I was thinking something like this....

Code:

void option1(struct *data);

int main()
{
     struct my_struct{
          int x;
          char y;
      } data;

 option1( data);
  .
  .
  .
     return o;
}
void option1(struct *data)
{
 // function stuff
}

or do i have to pass each element of the struct by itself.

Code:

void option1( int data.x, char data.y);

thanks
chris

Code:

#include <stdio.h>

struct bob{
        int x;
};

void pass(struct bob arg[50]);

int main(void){
        struct bob new[50];
        int x;
        pass(new);
        for(x=0;x<50;x++){
                printf("%d\n",new[x].x);
        }
        return 0;
}

void pass(struct bob arg[50]){
        int x;
        for(x=0;x<50;x++){
                arg[x].x=1;
        }
}

Of course I use 'x' too much

only if it is a pointer to a struct.

Man you guys are fast.

Thanks a bunch

chris

im still getting some warrnings

Code:

void option2(char *cat, struct data  *cars[50]);

int main()
{
struct data{
		char rank[2];
		char name[80];
		char state[12];
		char year[5];
		char category[2];
		char cost[10];
	};

	struct data cars[50];

     option2(cars);

     return;
}

void option2(char *cat, struct data  *cars[50])
{
//function stuff
}

thanks

Well you prototyped the function to take a pointer to a char and an array of pointers to structs but pass it only a pointer to a struct.

ok i fixed that, but its still not working.

Post the new code and the exact warnings/errors

check PMed it to ya thantos.

I checked the code and sent it back to you. Please note that its a bad idea to PM another member your code without asking first. I asked you to post it so that I or another member could comment on it and everyone would have the chance to learn.

Since you said you didn't want your code posted I won't but allow me to comment on it.

Arrays are not pointers but they can degenerate into pointers. So when you pass an array to a function that wants a pointer there is no need for the &. Example

Code:

char arr[100];
/* Improper scanf() */
scanf("%s", &arr);
/* Proper scanf() */
scanf("%s", arr);

Another note:

Code:

char *blah[10];

Declares a variable called blah that is an array of 10 pointers to characters