Thread: Variables number of arguments error

I'm having troubles parsing a variable list of arguments...

Code:

#include <stdarg.h>
#include <stdio.h>

void debug_output(const char *s, ...){
	va_list arglist;
//#ifdef _DEBUG
	if(!s) return;
	va_start(arglist, s);
	fprintf(stderr,s,arglist);
	va_end(arglist);
//#endif
}

int main(){
	debug_output("Exp 0\n");
	debug_output("Exp 1: %s\n","asd");
	debug_output("Exp 2: %s %s\n","abc","def");
	debug_output("Exp 3: %d\n",1);
	debug_output("Exp 4: %d %d\n",6,7);
	return 0;
}

And the output:

Code:

Exp 0
Exp 1: XPM
Exp 2: ,PM └↕
Exp 3: 1244976
Exp 4: 1244972 1245056

Clearly the list isn't being well formed... Any sugestions?

Try vfprintf().

gg

Yeap, vprintf worked. Thank you