Character Counting
How would I count the number of characters in a string?
Example:
GHfgHG235, etc.
and I want to know the number of times G, H, f, g, 2, etc., appears in the string?
I would assume that the string could be read into an array and then the counting would be no problem. But specifically how would I read the string into an array?
A string is a character array, each character in a string can be accessed.. string[1], string[2] etc..
The end of a string is signified by the '\0' character.. you could go through every character in the string until the character is '\0'
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How would you do it on paper? Write out the steps, then turn it into code.
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Originally Posted by glider_pilot123
You'd likely want to use either the scanf or the fgets functions:
Code:char string[80]; scanf("%s",string);Code:char string[80]; fgets(string,sizeof(string),stdin);
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Thanks hk_mp5kpdw. Being able to see the start of the code helps wonders.
The string is an array. If you use any of the standard C input functions, you can get a string from the user in the form of a null-terminated array. You can also specify a string literally. If i remember correctly it goes something like this:But specifically how would I read the string into an array?
Then just use a for loop to cycle through each element. Set it to stop when that character is null. The final value of the loop counter is the string length +/- 1, depending on how you implement it. In each cycle of the loop, just figure out your own way to keep track of the number of times a character has been called. I can think of a realy easy way involving an array of ints, indexed by ASCII numbers.Code:char string[10] = "Abcdefgh";
This is the same as gets()... Possible buffer overflow... i think
There's another active thread where the same subject is being treated.. Don't browse the page to the end unless you want code spoilers...
Last edited by xErath; 11-15-2004 at 06:01 PM.
