what is the output of this code fragment?

Code:

#define N_ELEMS 5

int main(void)
{
  int array[N_ELEMS];
  int i;

  for(i=0;i<N_ELEMS;i++)
    array[i]=i;

  for(i=0;i<N_ELEMS-1;)
    array[++i]++;

}

Hi, how do i know the output of this code??
i tried using this way, but the results seems dogey..any ideas why??

Code:

#define N_ELEMS 5
#include <stdio.h>

int main(void)
{
  int array[N_ELEMS];
  int i;

  for(i=0;i<N_ELEMS;i++)
  {
    array[i]=i;
  }
   printf("%i\n",array);

  for(i=0;i<N_ELEMS-1;)
  {
    array[++i]++;
  }  
    printf("%i\n",array);

return 0;
}

Pls advise me, thank u, is the printf which i have done a incorrect way??

You need another for loop and

Code:

printf( "%d ", array[i] );

Sorry salem,

where should this loop be then?? and shd the printf statement be array[i] or just array?? because i am printing the results of the array after the loop so i dont need the [i] right?? or am i wrong??

regards ryan

what you are doing is printing every array element in a loop, so you need a [i]