Slight difficulty with hourglass shape program

[tibu]

Hello. I've been trying to make an hourglass shape using any character the users inputs. I made the program but I can only make the top half of the hour glass with what i have right now. I just dont understand how to take the same code and make it so that it does the opposite after it gets to the middle of the hour glass. Here's what I have:

#include <stdio.h>
#include <stdlib.h>

int main ()
{int height, row, stars, spaces;
char symbol;

printf ("Enter a single character \n");
scanf ("%c", &symbol);

printf ("Enter an uneven integer between 1-19 \n");
scanf ("%d", &height);

for (row =height/2; row < height; row++) 
{ 
    for (spaces = 0; spaces < row; spaces ++) 
        printf(" "); 
    for (stars = 1; stars <  2 *  (height-row); stars++) 
        printf("%c", symbol); 
    printf("\n");

[itsme86]

I would do it like this:

itsme@itsme:~/C$ cat hourglass.c
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>

void draw_line(int row, int height, char symbol)
{
  int i;

  for(i = 0;i < row;++i)
    putchar(' ');
  for(;i < height-row;++i)
    putchar(symbol);
  putchar('\n');
}

int main(void)
{
  int height, row;
  char symbol;
  char buf[100];

  do
  {
    printf("Enter a single character: ");
    fflush(stdout);
    fgets(buf, sizeof(buf), stdin);
    symbol = *buf;
  } while(!isprint(symbol));

  do
  {
    printf("Enter an odd integer between 1 and 19: ");
    fflush(stdout);
    fgets(buf, sizeof(buf), stdin);
    height = atoi(buf);
  } while(height < 1 || height > 19 || !(height%2));

  for(row = 0;row < height/2;++row)
    draw_line(row, height, symbol);

  for(row = height/2;row >= 0;--row)
    draw_line(row, height, symbol);

  return 0;
}
itsme@itsme:~/C$ ./hourglass
Enter a single character: I
Enter an odd integer between 1 and 19: 19
IIIIIIIIIIIIIIIIIII
 IIIIIIIIIIIIIIIII
  IIIIIIIIIIIIIII
   IIIIIIIIIIIII
    IIIIIIIIIII
     IIIIIIIII
      IIIIIII
       IIIII
        III
         I
        III
       IIIII
      IIIIIII
     IIIIIIIII
    IIIIIIIIIII
   IIIIIIIIIIIII
  IIIIIIIIIIIIIII
 IIIIIIIIIIIIIIIII
IIIIIIIIIIIIIIIIIII
itsme@itsme:~/C$

[quzah]

This is a variation of the 'diamond' or 'pyramid' homework assignment. Search the forum for either of those and you should come up with a number of posts.

Quzah.

[tibu]

Think I got it:

#include <stdio.h>
#include <stdlib.h>


int main ()
{int x, y, num;
char symbol;

printf ("Enter a single character \n");
scanf ("%c", &symbol);

printf ("Enter an uneven integer between 1-19 \n");
scanf ("%d", &num);





     for (x= num / 2 ; x >= 1 ; x--)      
       {
           for(y = -num; y <= num - x; y++)
           {
               printf (" ");
           }
           for(y = 1; y <= 2*x- 1; y++) 
           {
               printf ("%c", symbol);
           }
           printf ("\n") ;
       }            
    
    




for(x = 2; x < num / 2 + 1; x++)
{
    for(y = -num; y <= num - x; y++)
    {
        printf (" ");
    }
    for(y = 1; y <= 2*x - 1; y++)
    {
        printf ("%c", symbol);
    }
    
        printf ("\n");
        
    }    
system("pause");        
        return 0;
       
}