Thread: Pointer question?

I want to display the string copied in sh().

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int sh(char * s)
{
	s = malloc(20);
	strcpy(s,"Hello World");
	return 0;
}

int  main()
{
        char *s=NULL;
        sh(s);
        printf("%s",s); /* Print Hello world*/
        return 0;
}

But its printing (null).
What's Wrong?

Do do it like that, you would need to pass a pointer to a pointer.

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int sh(char ** s)
{
	*s = malloc(20);
	strcpy(*s,"Hello World");
	return 0;
}

int  main()
{
        char *s=NULL;
        sh(&s);
        printf("%s",s); /* Print Hello world*/
        return 0;
}

try this ...

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int sh(char * s)
{
	s = malloc(20);
	strcpy(*s,"Hello World");
	return 0;
}

int  main()
{
        char *s=NULL;
        sh(s);
        printf("%s",s); /* Print Hello world*/
        return 0;
}