enumeration/endianess
When exchanging data (in my case usually integers) between big/little endian machines, I need to take care of proper byte ordering.
Now I need to exchange an enum and was wondering if the same rules apply and if I can assume enums to always have the same size as integers.
I assume I have to reorder bytes but since I'm not sure I thought I'd better ask.
main() { int O[!0<<~-!0]; (!0<<!0)[O]+= ~0 +~(!0|!0<<!0); printf("a function calling "); }
I think sizeof(an enum) == sizeof(int) all the time in C
IIRC, the rules are a little more complex for C++
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Thanks Salem!Originally Posted by Salem
I did some testing with different compiler options which seems to confirm that. Hopefully that's also true for non-GCC.
I'm still not 100% sure about the endianess issue, but since the enum is probably just a wrapped int, I'll just assume I need to correct byteordering.
main() { int O[!0<<~-!0]; (!0<<!0)[O]+= ~0 +~(!0|!0<<!0); printf("a function calling "); }
If you have then use the htonl() family of functions.
http://www.rt.com/man/htonl.3.html
http://www.rt.com/man/ntohl.3.html
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