This is a discussion on getcwd() function messes up my environment variable within the C Programming forums, part of the General Programming Boards category; Hi, I'm creating a shell and when I call the getcwd() function, it makes any environment variables I defined go ...
Hi, I'm creating a shell and when I call the getcwd() function, it makes any environment variables I defined go away. Here is an example:
int main()
{
char dir[500];
putenv("NEWDIR=/usr/bin");
system("env"); //NEWDIR shows up
getcwd(dir, 499);
system("env"); //NEWDIR is gone
return 0;
}
Any ideas?
maybe this should be in the linux programing forum
Your code works fine for me.
Hmm, can you try this Nessarose?
int main()
{
char *dirPtr;
char *path;
path = (char *)malloc(12);
strcpy(path, "NEWDIR=/usr");
putenv(path);
free(path);
std::cout << getenv("NEWDIR") << std::endl;
dirPtr = (char *)malloc(5);
std::cout << getenv("NEWDIR") << std::endl;
free(dirPtr);
return 0;
}
>> Hmm, can you try this Nessarose?
what exactly are you trying to do there? by the way - don't forget to use code tags, please...
Code:int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000 <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000 )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}
I ran it and it prints out /usr twice.
LinkBack URL
About LinkBacks
