Thread: Input and output

(1) If I wanted the following piece of code to input an integer and a character and print them, while assuming the user types as input 100 A, what corrections do I need:

.
.
.
scanf( "%d", &intVal );
charVal = getchar();
printf( "Integer: %d\nCharacter: %c\n", intVal, charVal);
.
.
.

(2) I want the piece of code to output even integers from 2 to 100.

.
.
.
counter = 2;

Do {

if (counter % 2 == 0)

printf ( "%d\n", counter );

counter += 2;

} While ( counter < 100);

1. You could do this whole thing with scanf:

Code:

int num;
char c;
printf("Enter number followed by character: ");
scanf("%d %c", &num, &c);
printf("Int: %d Cha: %c\n", num, c);

2. In your code, you have counter starting at 2, which makes it even. You don't have to make the check to see if (counter % 2 == 0) because you're incrementing it by 2 in the end. This means that the if statement will always be true since an even number + 2 will give you an even number. In any case, I don't see anything wrong with your code. It prints out even numbers fine on my end.