Thread: How does it work?

  1. #1
    Registered User
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    Jun 2004
    Posts
    123

    How does it work?

    Got this code to analyze.
    Code:
    int i,m,*g_p;
    int g[10]={1,5,3,4,0,22,8,0,-53,7};
    main()
    {
    	m=0;
    	g_p=g;
    	for (i=0;i<10;g_p++,m++,i++)
    	{
    			printf ("first loop: m=%d  *g_p=%d\n",m, *g_p);
    			printf ("\n");
    		for (;*g_p;g_p++,i++);
    			printf ("second loop: m=%d  *g_p=%d\n",m, *g_p);
    			printf ("\n");
    	}
    	printf ("end of program: m=%d  *g_p=%d\n",m, *g_p);
    }
    Figured out that it calculates the numbers of series, delimited by 0. I don’t understand:
    1. How does the pointer *g_p “jump” directly to 22 & then to -53.
    2. Why does it get the value of 0?
    3. What means the
    Code:
    *g_p
    in
    Code:
        for (;*g_p;g_p++,i++);
    output:
    first loop: m=0 *g_p=1

    second loop: m=0 *g_p=0

    first loop: m=1 *g_p=22

    second loop: m=1 *g_p=0

    first loop: m=2 *g_p=-53

    second loop: m=2 *g_p=0

    end of program: m=3 *g_p=0
    Last edited by ronenk; 08-16-2004 at 08:02 AM.

  2. #2
    Yes, my avatar is stolen anonytmouse's Avatar
    Join Date
    Dec 2002
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    2,544
    The behaviour of the program is undefined.

    It might help you understand the code if you change:
    Code:
    		for (;*g_p;g_p++,i++);
    to:
    Code:
    		for (;*g_p;g_p++,i++) /* Do nothing */;
    and analyse what this loop is doing.

  3. #3
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    Did that with out further understanding.

  4. #4
    Yes, my avatar is stolen anonytmouse's Avatar
    Join Date
    Dec 2002
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    Would it help you if I said:
    Code:
    for (;*g_p;g_p++,i++);
    is equivalent to:
    Code:
    while (*g_p != 0)
    {
        g_p++;
        i++;
    }
    Try running through the code step by step.

  5. #5
    ---
    Join Date
    May 2004
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    the style of that code looks ancient.

  6. #6
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    Jun 2004
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    OK now all understood!

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