Putchar

Ive been reading my book through out the course of my day and ive found my self reading this example and its output over & over again.

Code:

#include <stdio.h>

main()
{
         putchar(65);
              putchar(10);
                   putchar(66);
              putchar(10);
         putchar(67);
    putchar(10);
return 0;
}

now I get the gist of putchar but wat i dont get is why does it only prints
A
B
and not the other letters.

10 is the ASCII code for the character \n, so putchar(10) is the same as putchar('\n');

Originally Posted by Inferno

Ive been reading my book through out the course of my day and ive found my self reading this example and its output over & over again.

Code:

#include <stdio.h>

main()
{
         putchar(65);
              putchar(10);
                   putchar(66);
              putchar(10);
         putchar(67);
    putchar(10);
return 0;
}

now I get the gist of putchar but wat i dont get is why does it only prints
A
B
and not the other letters.

well you only have 4 different numbers - the numbers are ascii for A (65), B (66), and C(67) - the number 10 is '\n' or the newline character which makes your program display like this:

Code:

board $ ./putc
A
B
C
board $

as opposed to this:

Code:

ABC

by using this modified code:

Code:

#include <stdio.h>

int main(void)
{
    putchar(65);
/*    putchar(10); */
    putchar(66);
/*    putchar(10); */
    putchar(67);
/*    putchar(10); */
    return 0;
}

If you changed your original code.

edit:: beaten again!

~/

Try not to use direct references to ASCII numbers in your code, instead use the character constants. For example, this is a lot easier to understand/read:

Code:

 putchar ('A');
 putchar ('\n');
 putchar ('B');
 putchar ('\n');
 putchar ('C');
 putchar ('\n');

Of course, we're only playing with putchar() here, we wouldn't normally call it multiple times in succession to print out a few characters

hey thnxs yall