increasing series

this function run a series of numbers.
if n=3
out put is:
1,1,1
1,1,2
1,1,3
1,2,1
1,2,2
1,2,3
1,3,1
1,3,2
1,3,3

Please help me understand how the increasing process in this function works. I cann't see how the array's elemt increase their values.

Code:

---


void print_num(int n)
{
        int times;
        times=pow(n,2);
        while (times--)
        {
                for(i=0;i<n-1;i++)
                {
                        printf ("%d,", arr[i]);
                }
                printf ("%d\n",arr[i]);
                if (++arr[n-1]>n)
                {
                        arr[n-1]=1;
               
                        for(j=i-1;j>=0;j++)
                                if (++arr[j]>n)
                                arr[j]=1;
                                else
                                break;
                }
        }
}

---

if (++arr[n-1]>n)

++ is the prefix operator for addition

before arr[n-1]>n is evaluated ++arr[n-1] is executed and it increases arr[n-1] with 1.

Take a look at this link
http://crasseux.com/books/ctutorial/...---and---.html

This I know:

Quote:

---

++ is the prefix operator for addition

---

...and still don't get it.

From what I see in debugger I can tell the increment process happens in this loop:
[code]

for(i=0;i<n-1;i++)
{
printf ("%d,", arr[i]);
}
printf ("%d\n",arr[i]);

/[code]

on the other hand when put this in comment:

if (++arr[n-1]>n)

increment process doesn’t happen at all with output of:
1,1,1
1,1,1
1,1,1
1,1,1
1,1,1
1,1,1
1,1,1
1,1,1
1,1,1
please try to clarify it.

I'm not sure what you don't understand but..

if (++arr[n-1]>n)

++ has higher precedance then > so it get executed first.

You can see it like this

arr[n-1] = arr[n-1] + 1;

if(arr[n-1] >n )