Doesn't print out?
#include <stdio.h>
#include <string.h>
int main()
{
char str2[2], str1[2]= "a";
int n = 127;
str2[1] = 0;
str2[0] = n;
strcat(str1 , str2 );
if( str1[1] == n )
printf( "%s\n" , str1 );
return 0;
}
I don't know what's happenning. When n = 97, 98 ... 127, the printf prints out str1 but from n = 128 onwards, it doesn't print out anymore. Why and how do I fix it?
Try this:
unsigned char str2[2], str1[2]= "a";
unsigned int n = 240;
Analyze the table of int to char conversions. Maybe 128 is a different number. Theoretically, it should work (logically) out. char and int are interchangeable.
--Garfield
1978 Silver Anniversary Corvette
This is a no brainer:
The range of a 'char' is: -128/+127
Ok, so a "string" is what? It's an array of characters.
Given this, is it really a surprise that it doesn't print them?
for( c=-128; c < 128; c++ ) if( isprint(c) ) putc(c);
Quzah.
Hope is the first step on the road to disappointment.
quzah is right.
quzah, if I'm correct, don't you have to unsign the char to use the value of 128?
--Garfield
1978 Silver Anniversary Corvette
Yes for positive 128, but negative 128 is fine using two's complement.don't you have to unsign the char to use the value of 128?
zen
Yeah, that's what I thought.
1978 Silver Anniversary Corvette
I think you can't use the number 128 cause the number 128 is formed in the binary system by 10000000 and the fist bit on the left (the 1) is used to define if the number is positive or negative, cause that te maximum number you can write in binary is 1111111 = 127 (decimal)
Then you would need the 32-bit.
1978 Silver Anniversary Corvette
