Functions

[unanimous]

just a simple question:

what is the problem with this code:

#include <stdio.h>



void main()
{

int test(int number); /* function prototype */
int i;
int result = 0;


result = test(number);

for(i = 0; i < 20; i++)
printf("\n %d \n %d \n\a", i, result);
}

int test(int number)
{
number = 5;

return number;
}


and does a pointer have to have an astric (*) before it?

[jasrajva]

result = test(number);

now how can you do that

number by itself is a variable name local to your test fn so to do the above you must declare an int number in main or as a global

declare in after orbfrore yr test prototype as

int number = 0;

also void main should be
int main()
read the faqs to know why

[Garfield]

Yeah, you see, the scope of your var 'number' is not what you think it is:

int test(int number) 
{ 
number = 5; 

return number; 
}

'number' is only "seen" by this function as the parameter to the function.

result = test(number);

You never declared number as an int in 'main'. The correct code would be:

#include <stdio.h> 



void main() 
{ 

int test(int number); /* function prototype */ 
int i; 
int result = 0; 
int number;


result = test(number); 

for(i = 0; i < 20; i++) 
printf("\n %d \n %d \n\a", i, result); 
} 

int test(int number) 
{ 
number = 5; 

return number; 
}

And to your second question, a pointer has to have an * for declaration and to get the value of the pointer.

--Garfield