getting exact input

[chrismiceli]

I am bored and decided to take on a task. To get a number from the user without any flaw. It works for numbers, but if I enter 234a then it converts to 234 any ideas on how to change that

#include <stdio.h>
#include <stdlib.h>

int main(void){
        char buffer[BUFSIZ];
        int x;
        printf("Enter a number:  ");
        fflush(stdout);
        if(!(fgets(buffer,sizeof buffer,stdin)))
                exit(0);
        if(!(sscanf(buffer,"%d",&x)))
                exit(0);
        printf("%d is your number\n",x);
        return 0;
}

[linuxdude]

Sorry my brother must have logged on, on my computer. I posted this code above. I could isdigit ever element in the array but is there another way?

[Rouss]

Just keep it as a string, if you want it to print the 'a' too.

printf("%s is your number\n", buffer);

Unless you mean you want it to reject the input...

int i = 0;
int l = strlen(buffer);
while(i != l)
{
   printf("Enter a number:  ");
   if(!(fgets(buffer,sizeof buffer,stdin)))
                exit(0);
   for(i = 0; i < l; i++)
      if(!isdigit(buffer[i]))
          i = l + 1;
}
if(!(sscanf(buffer,"%d",&x)))
                exit(0);

I think that will do what you want... If you want it to reject invalid input.

// Sorry, was typing during your second post... Don't know of another way..

[linuxdude]

That is what I figured. Nice example excep the use of 1(num) and l(char) have a syntax highlighter that tells you if it is a num or not

[Rouss]

lol... I didn't even think about that... I just used l for length... Yeah... 1 != l... Just like O != 0.
D'0h.

[Dave_Sinkula]

but is there another way?

FAQ
(the strtol version may be of particular interest)

if(!(sscanf(buffer,"%d",&x)))

What about a return value of EOF?