Thread: Little more help for ME

Yes I have one more question for the great people at the C board.

What I am wonder ing is in the code below hoe does the function change() multiply *pnumber by 2 if *pnumber is not given a value in that function and is not globally declared?


#include <stdio.h>

int change(int* pnumber);

void main()
{
int number = 10;
int* pnumber = &number;
int result = 0;

result = change(pnumber);
printf("\n In main, result = %d\t number = %d", result, number);
}

int change(int* pnumber)
{
*pnumber *= 2;
printf("\n In function change, *pnumber = %d", *pnumber);
return *pnumber;
}

pnumber is passed to the function change()

result = change(pnumber);

therefore the value that pnumber points to can be multiplied by 2 in change() because change() has a copy of the pointer.

Hope that makes sense,

(: Ian