Thread: Command-line parameter problem

Code:

#include <stdio.h> 

int main (void)  
{ 
    int Counter; 

    for(Counter = 0; Counter < 5; Counter++) 
    { 
        printf("Loop process %d\n", Counter); 
        RunBatch(Counter); 
        printf("\n"); 
    } 
    return 0; 
} 

int RunBatch(int Counter) 
{ 
    int LoopCount = 0; 
    
    while(LoopCount < Counter) 
    { 
        LoopCount = LoopCount+1; 
        printf("This loop is on iteration %d.\n", LoopCount); 
    } 
    return 0; 
}

How would I change the second parameter in the above code located in the first for loop so that I may input what is currently 5, as any number from the command-line instead, hence filtering through the rest of the program and furthermore allowing control by means of one command line parameter.

Code:

int main ( int argc, char * argv[] )  
{
	if (argc == 2)
	{
		if(argv[1][0] == '?')
		{
			printf("Help stuff would go here.\n");
		}
		else
		{
			printf("%s \n", argv[1]); /* This is the line I'm trying to replace */
		}
	}
	else if ( argc >= 3 )
	{
		printf("Invalid input:\n");
		printf("Only one command-line parameter allowed.\n");
	}
	else
	{
		DefaultMessage();
	}
	return 0;
}

void DefaultMessage ( void )
{
	printf("CmdLine.exe:\n");
	printf("The purpose of this program is to demonstrate command line arguments.\n");
	printf("This program will print whatever you type on the screen.\n\n");
	printf("Example:\n");
	printf("C:\\>CmdLine.exe Hmmm\n");
	printf("Hmmm\n");
}

I tried culturing the first program into this one by means of a function call, and passing the 2nd command-line parameter straight to my function, but it doesn't register. My loop just spins out of control. I think that's because this command-line code I'm using captures text from the line, not raw integers - which is what I need for my idea, yes?

Any ideas?

I think you've been here far too long to have not read the FAQ

Sorry Salem, I let the atoi slip by me. That's what I needed. Thanks for pointing that out nonpuz.