Hello,i tried to solve the birthday problem with probabilities

and i have a problem,there is an error and i cant find it....

If you are patient plz look my source code and give me your ideas.

#1.This program returns the maximum number of people in a group

when at least 2 of them have a 50% probability to selebrate their birthday the same day.

#3.probality=success trials/number of trials

#4.the array gets random numbers in the interval [1,365] from rand()

I start with a group of 2 people ,the number of the group isnt bigger from 100 people.

#4a. number of people [2,100]

#5.I already solve this problem in a mathimatical form and i know for sure that the probability that at least 2 of them have a 50% to selebrate their birthday the same day when the group is composed by 23

people.

#6.i already isolated the problem but i dont know why this bring me an error )~~:

#7.The error is in the first for loop.If you munually put the number of people i.e people=23 you find the correct probab.(approximately 0.5).With the first loop my program is a total disaster.

Code:#include<stdio.h> #include<stdlib.h> int main() { int people,array[100],number,counter0,counter1,counter2; float probability,success_trials,limit=0.50,number_of_trials; printf("Enter the number of trials\n"); scanf("%f",&number_of_trials); for(probability=0.0,people=2;probability<limit;people++) { for (counter0=0;counter0<number_of_trials;counter0++) { for (counter1=0;counter1<people;counter1++) { number=array[counter1]=rand()%365+1; /*random numbers in the interval[1,365]*/ for (counter2=0;counter2<counter1;counter2++) { if (number==array[counter2]) /*we compare the first array element with the others and if we find a duplicated number then there are at least two people with the same birthday*/ { success_trials++; counter1=counter2=people; } } } } probability=success_trials/number_of_trials; } }#7.The error is in the first for loop.If you munually put the number of people i.e people=23 you find the correct probab.(approximately 0.5).With the first loop my program is a total disaster.put i need it to show the probability for 2,3,4...23 people

Code:#include<stdio.h> #include<stdlib.h> int main() { int people=23,array[100],number,counter0,counter1,counter2; float probability,success_trials,limit=0.50,number_of_trials; printf("Enter the number of trials\n"); scanf("%f",&number_of_trials); for (counter0=0;counter0<number_of_trials;counter0++) { for (counter1=0;counter1<people;counter1++) { number=array[counter1]=rand()%365+1; /*random numbers in the interval[1,365]*/ for (counter2=0;counter2<counter1;counter2++) { if (number==array[counter2]) /*we compare the first array element with the others and if we find a duplicated number then there are at least two people with the same birthday*/ { success_trials++; counter1=counter2=people; } } } } probability=success_trials/number_of_trials; printff("%f\n",probability); return 0; }