Thread: passing and recieving multi-dementional arrays

I'm writing a C program and I need to pass an array with 2 dementions to a function, but I don't know how to declare it as an arguement in the function parameters....

I'll pass, depending, either element "catagory[0]" or "catatory[1]", both have 5 elements in the 2nd demention, but within the function I need to be able to access either of them with the same receiving arguement, ie:

Code:

switch(x) {
 case 1:
  myfunction(catagory[0]);
  break;
 case 2:
  myfunction(catagory[1]);
  break
}

**end main**

void myfunction(*HOW TO RECEIVE THE ELEMENT?*) {
for (x=0; x < 5; x++) {
 printf("%c", *HOW TO USE THE ELEMENT AND IT'S 2ND DEMENTION*);
}
}

Is this clear?

Thanx


BTW: I'm new here, and somewhat new to C programming, I like this place, hope to be around for a while

Originally Posted by B-Con

I'm writing a C program and I need to pass an array with 2 dementions to a function, but I don't know how to declare it as an arguement in the function parameters....

I'll pass, depending, either element "catagory[0]" or "catatory[1]", both have 5 elements in the 2nd demention, but within the function I need to be able to access either of them with the same receiving arguement, ie:

Is the following close to what you are describing?

Code:

#include <stdio.h>

void foo(const char (*bar)[5])
{
   size_t i;
   for ( i = 0; i < sizeof *bar / sizeof **bar; ++i )
   {
      printf("%c", bar[0][i]);
   }
   putchar('\n');
   for ( i = 0; i < sizeof *bar / sizeof **bar; ++i )
   {
      printf("%c", bar[1][i]);
   }
   putchar('\n');
}

int main (void)
{
   const char ked[][5] =
   {
      {'a','b','c','d','e'},
      {'f','g','h','i','j'},
   };
   foo(ked);
   return 0;
}

/* my output
abcde
fghij
*/

Sort of...... but I can't use pointers, it's a small portion of a HW assignment, and the prof's unreachable till the next class.....

Here's excately what I have (the portions that matter), but I'm getting an "invalid indirection" error..... (ignore the "go" array, at least for now)

Code:

if (cat[round][0] == 'F' || cat[round][0] == 'f')
   vGetCat(go,catagory[0],5);
else if (cat[round][0] == 'N' || cat[round][0] == 'n')
   vGetCat(go,catagory[1],5);

***end main***

void vGetCat(char go[], char catagory[], int total)
{
   int idx;
   go[0] = getchar();
   for (idx=0; idx < total; idx++)
   {
      if (go[0] == catagory[0][idx])      <-- LINE THE COMPILER SAYS THE ERROR'S ON
         return;
   }

}

Would changing this

Code:

void foo(const char (*bar)[5])

to this

Code:

void foo(const char bar[][5])

allow you to pretend that there are no pointers?

Ah, it's working now..... thanx guys......

> vGetCat(go,catagory[0],5);
If catagory is a 2D array, what you're passing here is just one element of that array
Which would be a 1D array

> if (go[0] == catagory[0][idx])
Since its a 1D array, this would be
if (go[0] == catagory[idx])