Searching an array with pointers

The array and the pointer are both problems. If you pass an array to a function, just pass the name of the array, and nothing more. Like so:

Code:

int arrayfunction( int array[] )
{
    ...blah...
}

int main( void )
{
    int arrayofstuff[] = { 1, 2, 3, 4, 5, 6, 7 };

    arrayfunction( arrayofstuff );

    return 0;
}

Then see my previous posts for how to pass an integer or a pointer.

Quzah.

O, thats all it was. Ok, the [] just needed to be removed. Got it. Ill post the code in a sec. Beautiful. Thanks Dave


final code:

Code:

#include <stdio.h>
#include <stdlib.h>

#define TRUE 1
#define FALSE 0
#define N 10
int search (int a [], int n, int key){
int b;
 for(b=0; b<n; b++){
   if (key==*(a+b)){
       return TRUE;}
                                /*search for values with pointer*/
 }
return FALSE;
}

int main()
{
int k, j=9;
int array[]={10, 20, 13, 32, 50, 25, 40, 49, 11, 12};

k=10;
if (search(array,j,k)==TRUE){
  printf ("%d does exist\n", k);}
else if(search(array,j,k)==FALSE){
  printf ("%d does not exist\n", k);}

k=145;
if (search(array,j,k)==TRUE){
  printf ("%d does exist\n", k);}
else if(search(array,j,k)==FALSE){
  printf ("%d does not exist\n", k);}

k=15;
if (search(array,j,k)==TRUE){
  printf ("%d does exist\n", k);}
else if(search(array,j,k)==FALSE){
  printf ("%d does not exist\n", k);}

k=11;
if (search(array,j,k)==TRUE){
  printf ("%d does exist\n", k);}
else if(search(array,j,k)==FALSE){
  printf ("%d does not exist\n", k);}                        /*run function with values*/

      system("PAUSE");
}