Thread: A confusing syntax error

Here is a snippet of my program.

Code:

void
add_trans(Dict *dict, char *source, char *target)
{
    if (source != dict->*entry->source){
	dict->*entry->source = source;
	dict->size++;
	insert(dict->*entry->trans->target, target);
    }
}

While compiling it's giving me this error:

In function `add_trans':
error: syntax error before '*' token
error: syntax error before '*' token

Why is this syntaxt wrong?

Many thanks.

Code:

typedef struct {
    Entry **entries;
    int size;
    int max;
} Dict;

dict->*entry->source = source;

Look at the bolded sections.

Also is **entries a pointer to a pointer or a pointer an array of pointers?
If its an array of pointers like I'm thinking then you would need something like:

Code:

dict->entries[i]->source

Thantos,

Many thanks. A pointer to a pointer gives me a headache, but I think I got that one right by not omitting a pointer.

My compiler is giving me the same errors for these 2 lines:

Code:

if (source != dict->*entry->source){

Code:

insert(dict->*entry->trans->target, target);

Before that function I have already setup the insert function, but I don't think it's needed to post it. It's related to the syntax...

Originally posted by Thantos
Off the top of my head I'd say it should be

Code:

source != dict->(*entry)->source

Then it's giving the syntax error

Code:

parse error before '(' token

Tried to recreate your structures and heres what I got

Code:

#include <stdio.h>
#include <stdlib.h>

typedef struct
{
  char x;
  int y;
}Entry;

typedef struct
{
  Entry **test;
  int a;
  int b;
}Dict;

void foo (Dict *);

int main(void)
{
  Entry node={'b', 5}, *point=&node;
  Dict something={&point, 15, 20};

  foo (&something);
  return 0;
}
void foo (Dict *something)
{
  printf("%c %d %d %d\n",
      something->test[0]->x,
      something->test[0]->y,
      something->a,
      something->b);
}

I tried every other way I could think of but something->test[0]->x was the only way I could get it to work.